IMAT Logical Reasoning Questions Online Practice Test

IMAT Logical Reasoning Questions Online Practice Test and Sample Questions. Logical Reasoning Solved MCQS Questions with Answer Key.

46. Nine individuals: Ahmed, Bilal, Danish, Faisal, Haroon, Liaquat, Maryam, Shiza and Zeeshan are to serve on three committees labeled A, B and C. Each candidate should serve on exactly one of the committees. Every committee must have atleast one member. Committee A should consist of exactly one member more than that of committee B. Among Maryam, Shiza and Zeeshan none can serve on committee A. Among Faisal, Harron and Liaquat none can serve on committee B. Among Ahmed, Bilal and Danish none can serve on committee C. In case Danish and Zeeshan are the individuals serving on committee B, how many of the nine individuals should serve on committee C?
A. 2
B. 3
C. 4
D. 5

Answer: C
Explanation: If committee B has 2 members (Danish and Zeeshan), committee A must have exactly 3 members, leaving the remaining 4 individuals ($9 – 2 – 3 = 4$) to serve on committee C.

 

47. Of the nine individuals, the maximum number that can serve together on committee C is
A. 5
B. 6
C. 7
D. 8

Answer: B
Explanation: To maximize C, committees A and B must be minimized; since every committee needs at least 1 member and A needs 1 more than B, B gets 1 member and A gets 2 members, leaving a maximum of 6 members ($9 – 1 – 2 = 6$) for C.

48. In case Ahmed is the only individual serving on committee B, which among the following should serve on committee A
A. Bilal and Danish
B. Bilal and Faisal
C. Bilal and Liaquat
D. Faisal and Haroon

Answer: A
Explanation: If B has 1 member, A must have exactly 2 members; since Ahmed, Bilal, and Danish cannot join C, the remaining two (Bilal and Danish) must join A.

49. In case, any of the nine individuals serves on committee C, which among the following could not be the candidate to serve on committee A?
A. Ahmed
B. Bilal
C. Danish
D. Shiza

Answer: D
Explanation: The initial rules explicitly state that among Maryam, Shiza, and Zeeshan, none can serve on committee A.

 

50. In case, Bilal, Danish and Maryam are the only individuals serving on committee B, the total membership of committee C should be
A. 5
B. 4
C. 3
D. 2

Answer: D
Explanation: If B has 3 members, committee A must have 4 members ($3 + 1 = 4$), which leaves exactly 2 members ($9 – 3 – 4 = 2$) to serve on committee C.

51. In case, Bilal, Danish and Maryam are the only individuals serving on committee B, then the members of committee C should be
A. Haroon and Shiza
B. Maryam and Zeeshan
C. Shiza and Zeeshan
D. Faisal and Shiza

Answer: C
Explanation: With B having 3 members and A requiring 4 members, Ahmed (who cannot be on C) joins A along with Faisal, Haroon, and Liaquat, leaving Shiza and Zeeshan for committee C.

 

52. Among the following combinations which could constitute the membership of committee C
A. Danish and Shiza
B. Faisal and Maryam
C. Liaquat, Maryam and Shiza
D. Faisal, Haroon and Liaquat

Answer: B
Explanation: Combination B is possible because Danish cannot be on C (eliminating A), and combinations C and D would leave too few eligible members to properly satisfy the structural requirements of committees A and B.

 

53. If white is called black, black is called red, red is called yellow, yellow is called green, green is called blue, blue is called violet and violet is called orange, what would be the colour of human blood?
A. Green
B. Orange
C. Red
D. Yellow

Answer: D
Explanation: The real color of human blood is red, and according to the given code, “red is called yellow”.

54. Rahul, Prem, Shyam, Geet and Rinku are five friends among which Shyam is the tallest. Rahul is shorter than Prem but taller than Rinku. Geet is little shorter than Prem but little taller than Rahul. Who is taller than Rinku but shorter than Geet?
A. Rahul
B. Rinku
C. Prem
D. Geet

Answer: A
Explanation: Arranging their heights gives the order: $\text{Shyam} > \text{Prem} > \text{Geet} > \text{Rahul} > \text{Rinku}$, making Rahul the one who stands between Rinku and Geet.

56. 8(6+5) – 10 =?
A. 76
B. 78
C. 80
D. 82

Answer: B
Explanation: Following the order of operations, $8 \times (6 + 5) – 10 = 8 \times 11 – 10 = 88 – 10 = 78$.

 

58. From the given alternatives, select the word which CANNOT be formed using the letters of the “Demonstration”.
A. Moon
B. Most
C. Train
D. Damage

Answer: D
Explanation: The word “Damage” cannot be formed because the letter ‘g’ does not exist anywhere in the word “Demonstration”.

 

59. A can work twice as fast as B. A and C together can work three times as fast as B. if A, B and C complete a job in 30 days working together, in how many days can each of them complete the work.
A. 50,100,120
B. 60,120,120
C. 60,100,80
D. 40,80,100

Answer: B
Explanation: Let B’s efficiency be 1. Then A’s efficiency is 2, and since $A + C = 3$, C’s efficiency is 1. The total work is $(2 + 1 + 1) \times 30 = 120$ days, so individual times are $120/2 = 60$ days for A, $120/1 = 120$ days for B, and $120/1 = 120$ days for C.

 

60. A bus has exactly six stops on its route. The bus first stops at stop one and then at stops two, three, four, five, and six respectively. After the bus leaves stop six, the bus turns and returns to stop one and repeats the cycle. The stops are at six building that are, in alphabetical order L, M, N, O, P, and Q. P is the third stop. M is the sixth stop. The stop O is the stop immediately before Q. N is the stop immediately before L. In case N is the fourth stop, which among the following must be the stop immediately before P?
A. O
B. Q
C. N
D. L

Answer: B
Explanation: If N is stop 4, then L must be stop 5 (since N is immediately before L). With P at 3 and M at 6, the consecutive pair O-Q must fill stops 1 and 2, meaning Q is stop 2, which is immediately before P.

61. In case L is the second stop, which among the following must be the stop immediately before M?
A. L
B. P
C. O
D. Q

Answer: D
Explanation: If L is stop 2, then N must be stop 1 (since N is immediately before L). With P fixed at 3 and M fixed at 6, the consecutive pair O-Q must occupy stops 4 and 5, placing Q at stop 5, which is immediately before M.

62. In case a passenger gets on the bus at O, rides past one of the stops, and gets off at P, which of the following must be true?
A. O is stop one.
B. Q is stop three.
C. P is stop four.
D. N is stop five

Answer: A
Explanation: For a passenger to get on at O, ride past exactly one stop, and get off at P (which is stop 3), O must be positioned at stop 1 (riding past stop 2).

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